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reeseo3o
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Mar 21, 2026
| s_pali = re.sub(r'[^a-zA-Z0-9]', '', s).lower() | ||
| s_pali_reverse = s_pali[::-1] | ||
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| if s_pali == s_pali_reverse: |
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이 부분은 비교 연산 결과가 이미 bool이라 if/else 없이 return s_pali == s_pali_reverse 로 바로 리턴해도 될 것 같습니다! 😄
reeseo3o
reviewed
Mar 21, 2026
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| class Solution(object): | ||
| def hammingWeight(self, n): | ||
| binary = bin(n)[2:] |
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2진수 문자열로 변환해 1의 개수 세는게 직관적이어서 좋네요!
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