From 3b2006593001f1af41adb153d05a2f2dcc972aac Mon Sep 17 00:00:00 2001
From: ans-artal <92530185+ans-artal@users.noreply.github.com>
Date: Tue, 3 Mar 2026 17:32:19 +0100
Subject: [PATCH] fix: check readiness before timeout

I think that when a task completes as the timeout expire, the code should return the result rather than raise.
---
 taskiq/task.py | 2 +-
 1 file changed, 1 insertion(+), 1 deletion(-)

diff --git a/taskiq/task.py b/taskiq/task.py
index b4a0f52f..550dabee 100644
--- a/taskiq/task.py
+++ b/taskiq/task.py
@@ -98,9 +98,9 @@ async def wait_result(
         """
         start_time = time()
         while not await self.is_ready():
-            await asyncio.sleep(check_interval)
             if 0 < timeout < time() - start_time:
                 raise TaskiqResultTimeoutError(timeout=timeout)
+            await asyncio.sleep(check_interval)
         return await self.get_result(with_logs=with_logs)
 
     async def get_progress(self) -> "TaskProgress[Any] | None":