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Count_Inversions.py
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60 lines (45 loc) · 1.49 KB
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https://practice.geeksforgeeks.org/problems/inversion-of-array-1587115620/1?page=1&category[]=Arrays&sortBy=submissions
class Solution:
#User function Template for python3
# arr[]: Input Array
# N : Size of the Array arr[]
#Function to count inversions in the array.
def inversionCount(self, arr, n):
return self.mergeSort(arr, 0, n - 1)
def merge(self, arr, left, mid, right):
i = left
j = mid
k = 0
invCount = 0
temp = [0 for x in range(right - left + 1)]
while (i < mid) and (j <= right):
if arr[i] <= arr[j]:
temp[k] = arr[i]
k += 1
i += 1
else:
temp[k] = arr[j]
invCount += mid - i
k += 1
j += 1
while i < mid:
temp[k] = arr[i]
k += 1
i += 1
while j <= right:
temp[k] = arr[j]
k += 1
j += 1
k = 0
for i in range(left, right + 1):
arr[i] = temp[k]
k += 1
return invCount
def mergeSort(self, arr, left, right):
invCount = 0
if right > left:
mid = (right + left) // 2
invCount = self.mergeSort(arr, left, mid)
invCount += self.mergeSort(arr, mid + 1, right)
invCount += self.merge(arr, left, mid + 1, right)
return invCount